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Voltage drop (Read 946 times)
Nikk
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Re: Voltage drop
Reply #15 - Aug 8th, 2019 at 12:26pm
 
This what you looking for?



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Spence
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Re: Voltage drop
Reply #16 - Aug 8th, 2019 at 1:02pm
 
Nikk wrote on Aug 8th, 2019 at 12:26pm:
This what you looking for?





Exactly!
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Nikk
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Re: Voltage drop
Reply #17 - Aug 8th, 2019 at 2:51pm
 
Surprising the coil still managed to draw 4amps.
Thanks for sharing Spence.


Pooch made it home, has now lost her free roaming priviliges. Funny she has never wandered before, family reckons doggy dementia.
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Spence
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Re: Voltage drop
Reply #18 - Aug 8th, 2019 at 3:11pm
 
Nikk wrote on Aug 8th, 2019 at 2:51pm:
Surprising the coil still managed to draw 4amps.


So while under load what did you see as a voltage drop?

Would you normally consider this good?

Nikk wrote on Aug 8th, 2019 at 2:51pm:
Thanks for sharing Spence.


My pleasure! But we ain't done yet. Seems the others are letting you do all the work...

Nikk wrote on Aug 8th, 2019 at 2:51pm:
Pooch made it home, has now lost her free roaming priviliges. Funny she has never wandered before, family reckons doggy dementia.


Good to hear! (no pun intended)
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Nikk
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Re: Voltage drop
Reply #19 - Aug 9th, 2019 at 4:40am
 
I see a 7.1v voltage drop under load, no this is not good.



I would have expected just under battery voltage with some slight voltage drop whilst the coil was charging.
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Spence
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Re: Voltage drop
Reply #20 - Aug 9th, 2019 at 9:26am
 
Nikk wrote on Aug 9th, 2019 at 4:40am:
I see a 7.1v voltage drop under load,


Very good! That was pretty easy eh?

Nikk wrote on Aug 9th, 2019 at 4:40am:
no this is not good.


In most cases you would be correct. Keyword "most cases"... And if there's interest we can go further with this as well.

Nikk wrote on Aug 9th, 2019 at 4:40am:
I would have expected just under battery voltage with some slight voltage drop whilst the coil was charging.


Rule of thumb is 500 mv for entire circuit max.

Very good!   Smiley
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Nikk
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Re: Voltage drop
Reply #21 - Aug 9th, 2019 at 5:08pm
 
It looks like the coil amperage still got high enough to hit current limiting even though it was only pulling 4amps.
How much amperage did the coil pull after repair.


Always interested Spence.
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Spence
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Re: Voltage drop
Reply #22 - Aug 11th, 2019 at 6:49am
 
Sooooooo can we figure out the resistance that is in that circuit?
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Nikk
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Re: Voltage drop
Reply #23 - Aug 11th, 2019 at 6:46pm
 
We can using ohms law V/I but I am not sure I am correct using the unloaded circuit voltage 13.17v divided by current 4.04amps =3.26ohms.

As current starts to flow the resistance is going to change.


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Re: Voltage drop
Reply #24 - Aug 12th, 2019 at 3:44am
 
Nikk wrote on Aug 11th, 2019 at 6:46pm:
We can using ohms law V/I but I am not sure I am correct using the unloaded circuit voltage 13.17v divided by current 4.04amps =3.26ohms.

As current starts to flow the resistance is going to change.




You want the voltage at where the load is at 4.04 amps not the OCV(open circuit voltage). This is the whole reason for checking voltage drop.

Give it another shot.   Cool
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Logic
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Re: Voltage drop
Reply #25 - Aug 12th, 2019 at 3:56am
 
Spence wrote on Aug 12th, 2019 at 3:44am:
Nikk wrote on Aug 11th, 2019 at 6:46pm:
We can using ohms law V/I but I am not sure I am correct using the unloaded circuit voltage 13.17v divided by current 4.04amps =3.26ohms.

As current starts to flow the resistance is going to change.




You want the voltage at where the load is at 4.04 amps not the OCV(open circuit voltage). This is the whole reason for checking voltage drop.

Give it another shot.   Cool


Sorry, Wat are the points in the circuit that are open circuit as opposed to 4.04 amps?



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Re: Voltage drop
Reply #26 - Aug 12th, 2019 at 6:50am
 
Logic wrote on Aug 12th, 2019 at 3:56am:
Spence wrote on Aug 12th, 2019 at 3:44am:
Nikk wrote on Aug 11th, 2019 at 6:46pm:
We can using ohms law V/I but I am not sure I am correct using the unloaded circuit voltage 13.17v divided by current 4.04amps =3.26ohms.

As current starts to flow the resistance is going to change.




You want the voltage at where the load is at 4.04 amps not the OCV(open circuit voltage). This is the whole reason for checking voltage drop.

Give it another shot.   Cool


Sorry, Wat are the points in the circuit that are open circuit as opposed to 4.04 amps?





When no amperage is flowing.
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Nikk
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Re: Voltage drop
Reply #27 - Aug 12th, 2019 at 4:43pm
 
We then have just under 1.5ohms while current is flowing.

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James H
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Re: Voltage drop
Reply #28 - Aug 31st, 2019 at 8:43am
 
Spence, very sorry for the disappearing act and no timely reply, had a stressful family emergency that took me away from things for a while. I will read through and try to implement some of the great info you guys have provided, very much appreciated.
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Spence
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Re: Voltage drop
Reply #29 - Aug 31st, 2019 at 5:18pm
 
James H wrote on Aug 31st, 2019 at 8:43am:
Spence, very sorry for the disappearing act and no timely reply, had a stressful family emergency that took me away from things for a while.


No worries James! I hope all is well. Sorry to hear you were going through a rough spell.

James H wrote on Aug 31st, 2019 at 8:43am:
I will read through and try to implement some of the great info you guys have provided, very much appreciated.


Look forward to hearing from you. Let me know if there is something I can help with if needed.
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